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The statement BrArr((~A) vee B) is equiv...

The statement B`rArr((~A) vee B)` is equivalent to :

A

A`rArr(AhArrB)`

B

B`rArr(ArArrB)`

C

`BrArr((~A)rArrB)`

D

`ArArr((~A)rArrB)`

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AI Generated Solution

The correct Answer is:
To solve the logical statement \( B \rightarrow (\neg A \vee B) \), we will simplify it step by step. ### Step 1: Understand the implication The statement \( B \rightarrow (\neg A \vee B) \) can be rewritten using the definition of implication. Recall that \( P \rightarrow Q \) is equivalent to \( \neg P \vee Q \). So we can rewrite the statement as: \[ \neg B \vee (\neg A \vee B) \] ### Step 2: Apply Associative Law Using the associative law of disjunction, we can rearrange the terms: \[ \neg B \vee \neg A \vee B \] ### Step 3: Apply the Disjunctive Law Now, we can use the disjunctive law, which states that \( P \vee \neg P \) is always true (a tautology). Here, we have \( B \vee \neg B \): \[ (\neg B \vee B) \vee \neg A \] Since \( \neg B \vee B \) is a tautology (always true), we can simplify this to: \[ \text{True} \vee \neg A \] ### Step 4: Final Simplification Since anything ORed with true is true, we conclude that: \[ \text{True} \] Thus, the statement \( B \rightarrow (\neg A \vee B) \) is equivalent to a tautology. ### Conclusion The statement \( B \rightarrow (\neg A \vee B) \) is equivalent to **True**.
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