Let alpha x + beta y + gamma z = 1 be th...

Let `alpha x + beta y + gamma z = 1` be the equation of a plane passing through the point `(3, –2, 5)` and perpendicular to the line joining the points `(1,2,3) and (–2,3,5)`. Then the value of `alpha.beta.gamma` is equal to

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If the image of the point ( 1,-2,3) in the plane 2x + 3y -z =7 is the point ( alpha, beta , gamma ), then the value of alpha + beta + gamma is equal to

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Let A(-2,-1),B(1,0),C(alpha,beta) and D(gamma,delta) be the vertices of a parallelogram ABCD .If the point C lies on 2x-y=5 and the point D lies on 3x-2y=6 ,then the value of |alpha+beta+gamma+delta| is equal to:

Let the equation of the plane, that passes through the point (1, 4, - 3) and contains the line of intersection of the planes 3x - 2y + 4z -7 = 0 and x + 5y - 2z + 9 = 0, be alphax + betay + gammaz+3=0 , then alpha + beta + gamma is equal to :

Let L be a line obtained from the intersection of two planes x+2y+z = 6 and y+2z=4 . If point P(alpha,beta,gamma) is the foot of perpendicular from (3,2,1) on L then the value of 21(alpha+beta+gamma) equals .

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