A student is provided with a variable vo...

A student is provided with a variable voltage source V,a test resistor `R_T`=10`Omega`, two identical galvanometers `G_1` and `G_2` and two additional resistors,`R_1`=10M`Omega` and `R_2=0.001` `Omega`.For conducting an experiment to verify ohm's law,the most suitable circuit is:

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To verify Ohm's law, a student is provided with a test resistor R_T , a high resistance R_1 , a small resistance R_2 , two identical galvanometer G_1 and G_2 , and a variable voltage source V. The correct circuit to carry out the experiment is

To verify Ohm's law, a student is provided with a test resistor R_(T) , a high resistance R_(1) . a small resistance R_(2) , two identical galvometers G_(1) and G_(2) and voltage source V . The correct circuit to carry out the experiment is.

Two resistor R_(1) = (24 +- 0.5)Omega and R_(2) = (8 +- 0.3)Omega are joined in series, The equivalent resistence is

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

For two resistors R_1 and R_2 , connected in parallel, find the relative error in their equivalent resistance. if R_1=(50 pm2)Omega and R_2=(100 pm 3) Omega .

Two resistor of resistance R_(1)=(6+-0.09)Omega and R_(2)=(3+-0.09)Omega are connected in parallel the equivalent resistance R with error (in Omega)

Two resistors R_1 = (4 pm 0.8) Omega and R_2 (4 pm 0.4) Omega are connected in parallel. The equivalent resistance of their parallel combination will be :

Draw the circuit for experimental verification of Ohm's law using a source of variable DC voltage, a main resistance of 100 Omega , two galvanometers and two resistances of value 10^6 Omega and 10^-3Omega respectively. Clearly show the positions of the voltmeter and the ammeter.

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