A ring and a solid sphere rotating about an axis passing through their centres have same radii of gyration.The axis of rotation is perpendicular to plane of ring.The ratio of radius of ring to that of sphere is `sqrt(2/x)`. The value of x is

Radius of gyration of a ring about a transverse axis passing through its centre is

The moment of inertia of a solid sphere about an axis passing through the centre radius is 1/2MR^(2) , then its radius of gyration about a parallel axis t a distance 2R from first axis is

A ring of radius R having a linear charge density lambda moves towards a solid imaginary sphere of radius (R)/(2) , so that the centre of ring passes through the centre of sphere. The axis of the ring is perpendicular to the line joining the centres of the ring and the sphere. The maximum flux through the sphere in this process is

The radius of gyration of a rotating circular ring is maximum about following axis of rotation

Two identical rings A and B are acted upon by torques tau_(A) and tau_(B) respectively. A is rotating about an axis passing through the centre of mass and perpendicular ot the plane of the ring. B is rotating about a chord at a distance 1/(sqrt(2)) times the radius of the ring. If the angular acceleration of the ring is the same, then

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.

From a circular ring of mass M and radius R, an arc corresponding to a 90^(@) sector is removed. The moment of inertia of the ramaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is k times MR^(2). Then the value of k is

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is