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A plane P contains the line of intersect...

A plane P contains the line of intersection of the plane `vecr.(hati+hatj+hatk)=6` and `vecr.(2hati+3hatj+4hatk)=-5`.If P passes through the point `(0,2,-2)`, then the square of distance of the point `(12,12,18)` from the plane P is

A

155

B

620

C

310

D

1240

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The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

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Find the angle between the planes vecr.(3hati-4hatj+5hatk)=0 and vecr.(2hati-hatj-2hatk)=7 .

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