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The weight of a body on the earth is 400...

The weight of a body on the earth is `400 N`.Then weight of the body when taken to a depht half of the radius of the earth will be :

A

`Zero`

B

`200 N`

C

`100 N`

D

`300 N`

Text Solution

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The correct Answer is:
To solve the problem of finding the weight of a body when taken to a depth that is half of the radius of the Earth, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Given Information**: - The weight of the body on the surface of the Earth is given as \( W = 400 \, \text{N} \). - We need to find the weight of the body at a depth \( h = \frac{R}{2} \), where \( R \) is the radius of the Earth. 2. **Using the Formula for Weight at Depth**: - The formula for gravitational acceleration \( g' \) at a depth \( h \) is given by: \[ g' = g \left(1 - \frac{h}{R}\right) \] - Here, \( g \) is the acceleration due to gravity at the surface of the Earth. 3. **Substituting the Depth**: - Since \( h = \frac{R}{2} \), we substitute this into the formula: \[ g' = g \left(1 - \frac{\frac{R}{2}}{R}\right) \] - Simplifying this gives: \[ g' = g \left(1 - \frac{1}{2}\right) = g \left(\frac{1}{2}\right) \] - Thus, \( g' = \frac{g}{2} \). 4. **Relating Weight at Depth to Weight on Surface**: - The weight of the body at depth can be expressed as: \[ W' = m g' \] - Substituting \( g' \) from the previous step: \[ W' = m \left(\frac{g}{2}\right) \] - Since the weight at the surface is \( W = mg \), we can write: \[ W' = \frac{1}{2} W \] 5. **Calculating the Weight at Depth**: - Given \( W = 400 \, \text{N} \): \[ W' = \frac{1}{2} \times 400 \, \text{N} = 200 \, \text{N} \] ### Final Answer: The weight of the body when taken to a depth half of the radius of the Earth is \( W' = 200 \, \text{N} \).
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