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As shown in the figure,a configuration o...

As shown in the figure,a configuration of two equal point charges (`q_0`=+2`mu` C) is placed on an inclined plane. Mass of each point charge is 20 g.Assume that there is no friction between charge and plane. For the system of two point charges to be in equilibrium (at rest) the height `h = `xxx10^(-3)` m.
The value of x is
(Take `1/(4piepsilon_0)=9xx10^9Nm^2C^(-2)`,`g=10ms^(-2)`

Answer

Step by step text solution for As shown in the figure,a configuration of two equal point charges (q_0=+2mu C) is placed on an inclined plane. Mass of each point charge is 20 g.Assume that there is no friction between charge and plane. For the system of two point charges to be in equilibrium (at rest) the height h = xxx10^(-3) m.The value of x is(Take 1/(4piepsilon_0)=9xx10^9Nm^2C^(-2),g=10ms^(-2) by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Knowledge Check

  • As shown in the figure a charge +2 C is situated at the origin O and another charge +5 C is on the x -axis at the point A . The later charge from the point A is then brought to a point Bon the y - axis . The work done is ("given"(1)/(4piepsilon_(0))=9xx10^(9))

    A
    `45xx10^(9)J`
    B
    `90xx10^(9)J`
    C
    zero
    D
    `-45xx10^(9)J`

  • The electric field due to a charge at a distance of 3 m from it is 500 NC^(-1) . The magnitude of the charge is [(1)/(4 pi epsi_(0)) = 9 xx 10^(9) N - m^(2)//C^(2)]

    A
    `2.5 muC`
    B
    `2.0 muC`
    C
    `1.0 muC`
    D
    `0.5 muC`

  • What is the magnitude of a point charge due to which the electric field 30 cm away has the magnitude 2 ? [1//4piepsilon_0=9xx10^9N-m^2//c^2]

    A
    `2xx10^-11C`
    B
    `3xx10^-11C`
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    `5xx10^-11C`
    D
    `9xx10^-11C`

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