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The rms speed of oxygen molecule in a ve...

The rms speed of oxygen molecule in a vessel at particular temmperature is `(1+5/x)^(1/2)v` ,where v is the average speed of the molecule .the value of x will be : Given escape velocity on earth `V_e =11.2times 10^3 m/s)

A

`27`

B

`8`

C

`4`

D

`28`

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The correct Answer is:
To solve the problem, we need to find the value of \( x \) given the relationship between the root mean square (rms) speed of an oxygen molecule and its average speed. 1. **Understanding the given relationship**: The rms speed of an oxygen molecule is given as: \[ v_{\text{rms}} = \left(1 + \frac{5}{x}\right)^{1/2} v \] where \( v \) is the average speed of the molecule. 2. **Using the formulas for rms speed and average speed**: The formula for the rms speed \( v_{\text{rms}} \) is: \[ v_{\text{rms}} = \sqrt{\frac{3RT}{M}} \] and the average speed \( v \) is given by: \[ v = \sqrt{\frac{8RT}{\pi M}} \] 3. **Setting up the equation**: We can equate the two expressions for rms speed: \[ \sqrt{\frac{3RT}{M}} = \left(1 + \frac{5}{x}\right)^{1/2} \sqrt{\frac{8RT}{\pi M}} \] 4. **Canceling common terms**: Since \( \sqrt{\frac{RT}{M}} \) is common on both sides, we can simplify: \[ \sqrt{3} = \left(1 + \frac{5}{x}\right)^{1/2} \sqrt{\frac{8}{\pi}} \] 5. **Squaring both sides**: Squaring both sides to eliminate the square root gives: \[ 3 = \left(1 + \frac{5}{x}\right) \frac{8}{\pi} \] 6. **Rearranging the equation**: Rearranging this equation, we get: \[ 1 + \frac{5}{x} = \frac{3\pi}{8} \] 7. **Solving for \( \frac{5}{x} \)**: Subtracting 1 from both sides: \[ \frac{5}{x} = \frac{3\pi}{8} - 1 \] To combine the terms on the right, we convert 1 to a fraction: \[ 1 = \frac{8}{8} \implies \frac{5}{x} = \frac{3\pi - 8}{8} \] 8. **Finding \( x \)**: Inverting both sides gives: \[ x = \frac{5 \cdot 8}{3\pi - 8} = \frac{40}{3\pi - 8} \] 9. **Substituting \( \pi \)**: Using \( \pi \approx \frac{22}{7} \): \[ x = \frac{40}{3 \cdot \frac{22}{7} - 8} = \frac{40}{\frac{66}{7} - 8} \] Converting 8 to a fraction: \[ 8 = \frac{56}{7} \implies x = \frac{40}{\frac{66 - 56}{7}} = \frac{40 \cdot 7}{10} = 28 \] Thus, the value of \( x \) is \( 28 \).
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