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A vessel of depth 'd' is half filled wit...

A vessel of depth 'd' is half filled with oil of refractive index n_1 and the other half is filled with water of refractive index n_2 . The apparent depth of this vessel when viewed from above will be-

A

`(dn_1n_2)/(2(n_1+n_2))`

B

`(2d(n_1+n_2))/(n_1n_2)`

C

`(dn_1n_2)/((n_1+n_2))`

D

`(d(n_1+n_2))/(2n_1n_2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the apparent depth of a vessel that is half-filled with oil and half-filled with water, we can use the concept of apparent depth in optics. The apparent depth can be calculated using the formula for refraction at the interface of two media. ### Step-by-Step Solution: 1. **Identify the Depths and Refractive Indices**: - The vessel has a total depth \( D \). - The oil occupies the top half of the vessel, so its depth is \( \frac{D}{2} \) with refractive index \( n_1 \). - The water occupies the bottom half of the vessel, so its depth is also \( \frac{D}{2} \) with refractive index \( n_2 \). 2. **Calculate the Apparent Depth for Oil**: - The apparent depth \( d_1 \) of the oil layer can be calculated using the formula: \[ d_1 = \frac{h_1}{n_1} \] where \( h_1 = \frac{D}{2} \) is the actual depth of the oil. Thus, \[ d_1 = \frac{\frac{D}{2}}{n_1} = \frac{D}{2n_1} \] 3. **Calculate the Apparent Depth for Water**: - The apparent depth \( d_2 \) of the water layer can be calculated similarly: \[ d_2 = \frac{h_2}{n_2} \] where \( h_2 = \frac{D}{2} \) is the actual depth of the water. Thus, \[ d_2 = \frac{\frac{D}{2}}{n_2} = \frac{D}{2n_2} \] 4. **Combine the Apparent Depths**: - The total apparent depth \( d_{apparent} \) of the vessel when viewed from above is the sum of the apparent depths of the oil and water: \[ d_{apparent} = d_1 + d_2 = \frac{D}{2n_1} + \frac{D}{2n_2} \] 5. **Factor Out Common Terms**: - We can factor out \( \frac{D}{2} \): \[ d_{apparent} = \frac{D}{2} \left( \frac{1}{n_1} + \frac{1}{n_2} \right) \] 6. **Final Expression**: - Therefore, the final expression for the apparent depth of the vessel is: \[ d_{apparent} = \frac{D}{2} \left( \frac{1}{n_1} + \frac{1}{n_2} \right) \]
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