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In an electromagnetic wave, at an anstan...

In an electromagnetic wave, at an anstant and at a particular position , the electric field is along the negative z-axis and magnetic field is along the positive x-axis .Then the direction of propagation of electromagnetic wave is :

A

positive y-axis

B

negative y-axis

C

at `45^@` angle from positive y-axis

D

positive z-axis

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The correct Answer is:
To determine the direction of propagation of an electromagnetic wave given the orientations of the electric field (E) and the magnetic field (B), we can use the right-hand rule and the cross product of the two vectors. ### Step-by-Step Solution: 1. **Identify the Directions of E and B**: - The electric field (E) is given to be along the negative z-axis. We can represent this as: \[ \vec{E} = -E \hat{z} \] - The magnetic field (B) is along the positive x-axis. We can represent this as: \[ \vec{B} = B \hat{x} \] 2. **Use the Right-Hand Rule**: - The direction of propagation of an electromagnetic wave is given by the cross product of the electric field and the magnetic field: \[ \vec{k} \propto \vec{E} \times \vec{B} \] - To find the direction of \(\vec{E} \times \vec{B}\), we can use the right-hand rule. Point your fingers in the direction of \(\vec{E}\) (negative z-axis) and curl them towards \(\vec{B}\) (positive x-axis). 3. **Calculate the Cross Product**: - The cross product \(\vec{E} \times \vec{B}\) can be calculated as follows: \[ \vec{E} \times \vec{B} = (-E \hat{z}) \times (B \hat{x}) \] - Using the properties of the cross product: \[ \hat{z} \times \hat{x} = -\hat{y} \] - Therefore: \[ \vec{E} \times \vec{B} = -EB (\hat{z} \times \hat{x}) = -EB (-\hat{y}) = EB \hat{y} \] 4. **Determine the Direction of Propagation**: - Since \(\vec{E} \times \vec{B}\) gives us a vector in the positive y-direction, the direction of propagation of the electromagnetic wave is along the positive y-axis. 5. **Final Answer**: - Thus, the direction of propagation of the electromagnetic wave is along the positive y-axis.
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