A straight wire AB of mass `40`g and length `50` cm is suspended by a pair of flexible leads in unifrom magnetic field of magnitude `0.40` T as shown in the figure .The magnitube of the current required ih the wire to remove the tension in the supporting leads is ______A.(Take `g = 10 ms^(-2))`

A wire of 62.0 cm length and 13.0 g mass is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440 T in figure. What are the magnitude and direction of the current required to remove the tension in the supporting leads? Take g = 10 m/s^2

A wire of 60 cm length and mass 16 gm is suspended by a pair of flexible leads in a magnetic field of induction 0.40 T. What are the magnitude and direction of the current required to remove the tension in the supporting leads?

A straight conductor of length 60cm and mass 10gm is suspended horizontally by a pair of flexible leads in a magnetic field of 0.4T as shown in figure. A current at 0.41A should be passed through the conductor to just remove the tension in the supporting cable. The total tension in the leads if the direction of current is reversed is found 1.96xx10^(-y)N . Find y ?

A straight wire of length 50 cm carrying a current of 2.5 A is suspended in mid-air by a uniform magnetic field of 0.5 T (as shown in figure). The mass of the wire is (g = 10 ms^(-2) )

A straight wire of mass 200 g and length 1.5 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B. What is the magnitude of the magnetic field?

An iron rod of mass 50 g and length 50 cm is suspended by master wires as shown in the figure. Calculate the magnitude and direction of magnetic field to be set in the region such that the tension is the wires is zero. The current in the rod is 4 A.

A straight wire of mass 400 g and length 2m carries a current of 2A. It is suspended in mid air by a uniform horizontal field B. What is the magnitude of the magnetic field ?

A conducting rod of 1 m length and 1 kg mass is suspended by two verticle wires through its ends. An external magnetic field of 2T is applied normal to the rod. Now the current to be passed through the rod so as to make the tension in the wire zero is [Take g = 10 ms^(-2)]