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Statement (P implies Q) vv(R implies Q) ...

Statement `(P implies Q) vv(R implies Q)` Is logically equivalent to

A

`(P implies R) vv (Q implies R)`

B

`(PvvR)impliesQ`

C

`(P implies R)^^(Q implies R)`

D

`(P^^R)impliesQ`

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The correct Answer is:
To determine the logical equivalence of the statement \( (P \implies Q) \lor (R \implies Q) \), we can follow these steps: ### Step 1: Rewrite the implications The implication \( P \implies Q \) can be rewritten using logical equivalences. Recall that \( P \implies Q \) is equivalent to \( \neg P \lor Q \). Similarly, \( R \implies Q \) can be rewritten as \( \neg R \lor Q \). Thus, we can rewrite the original statement: \[ (P \implies Q) \lor (R \implies Q) = (\neg P \lor Q) \lor (\neg R \lor Q) \] ### Step 2: Apply the Associative Law Using the associative law of disjunction, we can rearrange the terms: \[ (\neg P \lor Q) \lor (\neg R \lor Q) = \neg P \lor \neg R \lor Q \] ### Step 3: Factor out common terms Notice that \( Q \) appears in both parts of the disjunction. We can factor it out: \[ \neg P \lor \neg R \lor Q = Q \lor (\neg P \lor \neg R) \] ### Step 4: Rewrite using implications The expression \( \neg P \lor \neg R \) can be rewritten as \( \neg (P \land R) \) using De Morgan's laws. Therefore, we have: \[ Q \lor \neg (P \land R) \] ### Step 5: Final implication form This can be interpreted as: \[ \neg (P \land R) \lor Q \] This is equivalent to: \[ (P \land R) \implies Q \] ### Conclusion Thus, the original statement \( (P \implies Q) \lor (R \implies Q) \) is logically equivalent to: \[ (P \land R) \implies Q \]
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