If the maximum load carried by an elevator is 1400 kg (600 kg – Passengers + 800 kg - elevator), which is moving up with a uniform speed of 3 m `s^(–1)` andthe frictional force acting on it is 2000 N, then the maximum power used by the motor is _______kW (g = 10 `m/s^2`)

An elevator can carry a maximum load of 1800 kg (celevator + passengers) is moving up with a constant speed of 2 ms^(-1) . The friction force oppposite the motion is 4000 N .What is minimum power delivered by the motor to the elevator?

An elevator that can carry a maximum load of 1500 kg (elvator+ passengers) is moving up with a constant speed of 2 ms^(-1). The frictional force opposing the motion is 3000 N. Find the minmum power delvered by the motor to the elevator in watts as well as in horse power (g=10ms^(-2))

An elevator which can carry a maximum load of 1800kg is moving with a constant speed of 2ms^(-1) . The frictional force opposing the motino is 5000N . Calculate the minimum power delivered by the motor to the elevator in watt and hp ? Take g=10m//s^(2)

A lorry of mass 2000 kg is traveling up a hill of certain height at a constant speed of 10 m/s. The frictional resistance is 200 N, then the power expended by the coolie is : (g=10 m//s^(2))

A body of mass 1kg is moving with a uniform speed of 1m//s in a circular path of radius 1m . The external force acting on the body is

A body of mass 5kg is moving along a circle of radius 1m with a uniform speed of 5m//s . The external force acting on the body is

A bolt of mass 0.2 kg falls from the ceiling of an elevator moving down with a uniform speed of 5 m s^(-1) . It hits the floor of the elevator (length of the elevator = 5 m) and does not rebound. The amount of heat produced by the impact is (Take g = 10 m s^(-2) )

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :