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If A=1/(5!6!7!)[[5!,6!,7!],[6!,7!,8!],[7...

If `A=1/(5!6!7!)[[5!,6!,7!],[6!,7!,8!],[7!,8!,9!]]`, then `|adj(adj(2A))|` is equal to

A

`2^(20)`

B

`2^8`

C

`2^(12)`

D

`2^(16)`

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