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Let the line x/1=(6-y)/2=(z+8)/5 interse...

Let the line `x/1=(6-y)/2=(z+8)/5` intersect the lines `(x-5)/4=(y-7)/3=(z+2)/1` and `(x+3)/6=(3-y)/3=(z-6)/1` at the points A and B respectively. Then the distance of the mid-point of the line segment AB from the plane `2x-2y+z=14` is

A

3

B

`11/3`

C

4

D

`10/3`

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