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Let the line passing through the points `P (2, -1, 2) and Q (5, 3, 4)` meet the plane `x - y + z =4` at the point R. Then the distance of the point R from the plane `x + 2y + 3z + 2 = 0` measured parallel to the line `(x-7)/2=(y+3)/2=(z-2)/1` is equal to

A

3

B

`sqrt(31)`

C

`sqrt(61)`

D

`sqrt(189)`

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