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Let the tangent to the parabola y^2 = 12...

Let the tangent to the parabola `y^2 = 12x` at the point `(3, alpha)` be perpendicular to the line `2x + 2y = 3`. Then the square of distance of the point `(6, -4)` from the normal to the hyperbola `alpha^2 x^2-9y^2=9alpha^2` at its point `(alpha-1 , alpha + 2)` is equal to

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