A particle was having `v=5i` at origin and was acted by acceleration `a=3hati+2hatj`. At a moment Its x-coordinate was 84, then magnitude of its velocity is `sqrtalpha, alpha=?`

A particle has an initial velocity of 4 hati +3 hatj and an acceleration of 0.4 hati + 0.3 hatj . Its speed after 10s is

A particle has an initial velocity of 3hati+ 4hatj and an acceleration of 0.4hati +0.3hatj Its speed after 10 s is

A particle has an initial velocity 3hati+4hatj and an accleration of 0.4hati+0.3hatj . Its speed after 10s is

A particle has an initial velocity of 3hati + 4hatj and on acceleration of 0.4hatj + 0.3hatj . The magnitude of its velocity after 10 s is

Starting from the origin at time t = 0 , with initial velocity 5hatj "ms"^(-1) , a particle moves in the x - y plane with a constant acceleration of (10hati+4hatj)ms^(-2) . At time t , its coordinates are (20 m,y_0 m) . The value of t and y_0 are , respectively :

If angular velocity of a particle having position vector vec r = (2hati - 2hatj + 2hatk)m about the origin is vec w = (2hati - 2hatj - hatk)rad/s then magnitude of linear velocity of the particle will be

A particle leaves the origin with an initial velodty v= (3.00 hati) m//s and a constant acceleration a= (-1.00 hati-0.500 hatj) m//s^2. When the particle reaches its maximum x coordinate, what are (a) its velocity and (b) its position vector?

A particle has initial velocity (2hati+3hatj) and acceleration (0.3hati+0.2hatj) . The magnitude of velocity after 10 second will be

A particle moves in plane with acceleration veca = 2hati+2hatj . If vecv=3hati+6hatj , then final velocity of particle at time t=2s is