The refracting angle of a prism is `A`, the refractive index of the material of the prism is `cot((A)/(2))`. The angle of minimum deviation is :

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A)/(2) . The angle of minimum deviation is

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A//2). the angel of minimum deviation is

The refracting angle of a prism is A and refractive index of the material of the prism is cos(A//2) . The angle of minimum deviation is

The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be

The refracting angle of the prism is 60^@ and the refractive index of the material of the prism is sqrt(3) . Calculate the angle of minimum deviation in degree.

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .

The refractive index of the material of prism sqrt3, then the angle os minimum deviation of prism is

The refractive index of the material of an equilateral prism is 1.6. The angle of minimum deviation due to the prism would be