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The length of the chord of the ellipse (...

The length of the chord of the ellipse `(x^(2))/(25)+(y^(2))/(16)=1` ,whose mid point is `(1,(2)/(5))` ,is equal to :

A

`(sqrt(2009))/(5)`

B

`(sqrt(1691))/(5)`

C

`(sqrt(1741))/(5)`

D

`(sqrt(1541))/(5)`

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Find the length of the chord of the ellipse (x^(2))/(25)+(y^(2))/(16)=1, whose middle point is ((1)/(2),(2)/(5))

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Knowledge Check

  • Find the length of the major axis of the ellipse (x^2)/( 25) + (y^2)/( 16) =1 .

    A
    10
    B
    8
    C
    9
    D
    20

  • The mid point of the chord 16x+9y=25 to the ellipse (x^(2))/(9)+(y^(2))/(16)=1 is

    A
    (1,-1)
    B
    (-1,1)
    C
    (-1,1)
    D
    (1,1)

  • The length of the latusrectum of the ellipse 16x^(2)+25y^(2)=400 is

    A
    5/16 units
    B
    32/5 units
    C
    16/5 units
    D
    5/32 units

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    Statement-1 : The condition on a and b for which two distinct chords of the ellipse (x^(2))/(2a^(2))+(y^(2))/(2b^(2))=1 passing through (a,-b) are bisected by theine x+y=b "is" a^(2)+6ab-7b^(2) ge0 . Because: Statement-2 equation of chord of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 whose mid point is (x_(1),y_(1)) is T=S_(1)

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