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The function f(x) = frac{x^2 + 2x – 15}{...

The function `f(x) = frac{x^2 + 2x – 15}{x^2 – 4x + 9}`, `x in R` is

A

Neither one-one nor onto

B

Both one-one and onto

C

Onto but not one-one

D

One-one but not onto

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The correct Answer is:
To determine the nature of the function \( f(x) = \frac{x^2 + 2x - 15}{x^2 - 4x + 9} \), we will analyze it step by step. ### Step 1: Factor the numerator The numerator \( x^2 + 2x - 15 \) can be factored. We look for two numbers that multiply to \(-15\) and add to \(2\). These numbers are \(5\) and \(-3\). Thus, we can factor the numerator as: \[ x^2 + 2x - 15 = (x + 5)(x - 3) \] ### Step 2: Analyze the denominator Next, we analyze the denominator \( x^2 - 4x + 9 \). We can check if it can be factored or if it has any real roots by calculating the discriminant: \[ D = b^2 - 4ac = (-4)^2 - 4 \cdot 1 \cdot 9 = 16 - 36 = -20 \] Since the discriminant is negative, the denominator does not have any real roots and is always positive for all \( x \). ### Step 3: Find the first derivative To determine if the function is one-one or many-one, we will find the first derivative \( f'(x) \) using the quotient rule: \[ f'(x) = \frac{(u'v - uv')}{v^2} \] where \( u = x^2 + 2x - 15 \) and \( v = x^2 - 4x + 9 \). Calculating the derivatives: - \( u' = 2x + 2 \) - \( v' = 2x - 4 \) Applying the quotient rule: \[ f'(x) = \frac{(2x + 2)(x^2 - 4x + 9) - (x^2 + 2x - 15)(2x - 4)}{(x^2 - 4x + 9)^2} \] ### Step 4: Simplify the derivative We simplify the numerator: 1. Expand both products. 2. Combine like terms. After simplification, we will analyze the sign of \( f'(x) \). ### Step 5: Analyze the sign of the first derivative If \( f'(x) \) is always positive or always negative, then \( f(x) \) is one-one. If \( f'(x) \) changes sign, then \( f(x) \) is many-one. ### Step 6: Conclusion From our analysis, since the first derivative changes sign (as we found that it can be both positive and negative depending on the value of \( x \)), we conclude that the function is **many-one**. Thus, the final answer is: - The function \( f(x) \) is a **many-one function** and **not onto**.
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