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Find the sum to n terms of the series, w...

Find the sum to n terms of the series, whose `n^(t h)`terms is given by : `n^2+2^n`

Text Solution

Verified by Experts

Given `sum(n^2+2^n)`
`=>sumn^2+sum2^n`
`=(n(n+1)(2n+1))/6+(1(2(2^n)-1))/(2-1)`
`=(n(n+1)(2n+1))/6+(2(2^n)-1)/(1)`
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