`tan phi cosec phi = sec phi`

If 3(cot^2 phi-cos^2 phi)=cos^2 phi, 0^@ < phi < 90^@ , then the value of (tan^2 phi +cosec^2 phi + sin^2 phi) is:

The value of tan^2 phi+ cot^2 phi- sec^2 phi cosec^2 phi is equal to:

The value of (sec phi(1-sin phi)(sin phi+cos phi) (sec phi+tan phi))/(sin phi(1+tan phi)+cos phi(1+ cot phi)) is equal to :

The value of sqrt((cosec phi-cot phi)/(cosec phi +cot phi)) div (sin phi)/(1+cos phi) is equal to:

If x = sec phi - tan phi and y = cos ec phi + cot phi , then

The coordinates of a point are ( 4tan phi , 3 sec phi ) where phi is a parameter , then the point lies on a conic section whose eccentricity is

If sqrt(a + b) tan = theta/2 = sqrt(a -b) tan phi/2 then prove that a + b cos phi = (a cos phi+ b) sec theta .

If x=sec phi-tan phi and y=csc phi+cot phi then x=(y+1)/(y-1)( b) x=(y-1)/(y+1)y=(1+x)/(1-x)(d)xy+x-y+1=0

phi is an acute angle such that tan phi=(2)/(3) then evaluate ((1+tan phi)/(sin phi+cos phi))*((1-cot phi)/(sec phi+csc phi ))

If x=sec phi-tan phi and y=cos ec phi+cot phi then