Find the sum to n terms of the series :`1^2+(1^2+2^2)+(1^2+2^2+3^2)+...............`

Explanation

To find the sum to n terms of the series \( S_n = 1^2 + (1^2 + 2^2) + (1^2 + 2^2 + 3^2) + \ldots \), we can break it down step by step.

### Step 1: Understand the Series
The series can be rewritten as:
\[ S_n = 1^2 + (1^2 + 2^2) + (1^2 + 2^2 + 3^2) + \ldots + (1^2 + 2^2 + 3^2 + \ldots + n^2) \]
This means we are summing the squares of the first \( k \) natural numbers for each \( k \) from 1 to \( n \).
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