In sinA=sinB and cos A=cos B, then prove...

In `sinA=sinB` and `cos A=cos B`, then prove that `sin(A-B)/(2)=0`

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To prove that \(\frac{\sin(A - B)}{2} = 0\) given that \(\sin A = \sin B\) and \(\cos A = \cos B\), we can follow these steps: ### Step 1: Understand the implications of the given equations From the equations \(\sin A = \sin B\) and \(\cos A = \cos B\), we can infer that angles \(A\) and \(B\) are either equal or differ by a multiple of \(2\pi\). ### Step 2: Use the sine and cosine difference identities Since \(\sin A = \sin B\), we can write: \[ ...

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right angled

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ospsceles

equilateral

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