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If n is an odd positive interger, then ...

If n is an odd positive interger, then
`((cosA+cosB)/(sinA-sinB))^(n)+((sinA+sinB)/(cosA-cosB))^(n)=`

Text Solution

Verified by Experts

LHS`=((2cos(A+B)/(2)cos(A-B)/(2))/(2cos(A+B)/(2)sin(A-B)/(2)))^(n)`
`+((2sin(A+B)/(2)cos(A-B)/(2))/(2sin(A+B)/(2)sin(B-A)/(2)))^(n)`
`=(cot(A-B)/(2))^(n)+(-cot(A-B)/(2))^(n)`
`[because sin(-theta)=-sintheta]`
`=cot^(n)(A-B)/(2)+(-1)^(n)cot(n)(A-B)/(2)`
`=cot^(n)(A-B)/(2)[1+(-1)^(n)]`
`={0, "if n is odd" 2 cot^(n)(A-B)/(2)`, if n is even.
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