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Prove that sin6^0sin42^0sin66^0sin78^0-1...

Prove that `sin6^0sin42^0sin66^0sin78^0-1/(16)`

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`sin 6^(@) sin 42^(@) sin 66^(@)sin 78^(@)`
`=sin 6^(@)cos48^(@)cos 24^(@) cos 12^(@)`
`=sin6^(@)(2^(3)sin12^(@)cos 12^(@)cos24^(@)cos48^(@))/(2^(3)sin 12^(@))`
`=sin6^(@)(sin96^(@))/(2^(3)sin 12^(@))`
`=(2sin6^(@)cos6^(@))/(2^(4)sin12^(@))`
`=(sin 12^(@))/(2^(4)sin12^(@))`
`=(1)/(16)`
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