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If (cos6x+6cos4x+15cos2x+10)/(cos5x+5cos...

If `(cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=1`, then find the smallest positive value of x.

Text Solution

Verified by Experts

The correct Answer is:
`x=60^(@)`

`(cos 6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=1`
`rArr((cos 6x+cos 4x)+5(cos4x+cos2x)+10(cos2x+1))/(cos5x+5cos 3x+10cosx)=1`
`rArr (2cos x[cos 5x+5cos 3x+10cosx])/(cos 5x+5cos2x+10cos x)=1`
`rArr cos x=(1)/(2)`
`therefore x=60^(@)`.
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