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If A=sin45^0+cos45^0a n dB=sin44^0, then...

If `A=sin45^0+cos45^0a n dB=sin44^0,` then A>B (b) A

A

`AgtB`

B

`AltB`

C

`A=B`

D

none of these.

Text Solution

Verified by Experts

The correct Answer is:
A
`A=(1)/sqrt(2)+(1)/sqrt(2)=sqrt(2)sin90^(@)`
`B=sqrt(2)[(1)/sqrt(2)sin44^(@)+(1)/sqrt(2)cos44^(@)]`
`=sqrt(2)sin(45^(@)+44^(@))`
`=sqrt(2)sin 89^(@)ltsqrt(2)sin 90^(@)`
`sqrt(2) therefore AgtB` .
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