In triangle A B C , if sinAcosB=1/4 and ...

In triangle `A B C ,` if `sinAcosB=1/4 and 3t a n A=t a n B ,t h e ncot^2A` is equal to

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The correct Answer is:

`3 sin A cos B=sin B cos A`
`rArr cos A sin B =(3)/(4)`
`rArr C=(pi)/(2).B=(pi)/(2)-A`
`rARr 3tan A=tan ((pi)/(2)-A)`
`rArr 3=cot^(2)A`.

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