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if (1+tanalpha)(1+tan4alpha) =2 where al...

if (1+tan`alpha`)(1+tan4`alpha`) =2 where `alpha` `in` (0 , `pi/16`) then `alpha ` equal to

A

`(pi)/(20)`

B

`(pi)/(30)`

C

`(pi)/(40)`

D

`(pi)/(60)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1+tanA)(1+tanB)=2`
`rArr tan A+tan B=1-tan A tan B`
`rARr tan(A+B)=1,i.e, A+B=(pi)/(4)`
or `alpha+4alpha=(pi)/(4)` i.e. `alpha=(pi)/(20)`
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