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Value of (3+cot80^0cot20^0)/(cot80^0+cot...

Value of `(3+cot80^0cot20^0)/(cot80^0+cot20^0)` is equal to

A

`cot20^(@)`

B

`tan 50^(@)`

C

`cot50^(@)`

D

`cotsqrt(20^(@))`

Text Solution

Verified by Experts

The correct Answer is:
B
`([3+(cos 80^(@)cos20^(@))/(sin80^(@)sin20^(@))])/([(cos 80^(@))/(sin80^(@))+(cos20^(@))/(sin20^(@))])`
`=([2sin80^(@)sin20^(@)+(cos 80^(@)cos20^(@)sin80^(@)sin20^(@))])/(sin20^(@)cos80^(@)+cos20^(@)sin80^(@))`
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