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(sqrt2-sinalpha-cosalpha)/(sinalpha-cosa...

`(sqrt2-sinalpha-cosalpha)/(sinalpha-cosalpha)` is equal to

A

`sec((alpha)/(2)-(pi)/(8))`

B

`cos((pi)/(8)-(alpha)/(2))`

C

`tan((alpha)/(2)-(pi)/(8))`

D

`cot((alpha)/(2)-(pi)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`(sqrt(2)-sin alpha-cosalpha)/(sin alpha-cos alpha)`
`=(sqrt(2)-sqrt(2)((1)/sqrt(2)sin alpha+(1)/sqrt(2)cos alpha))/(sqrt(2)((1)/sqrt(2)sin alpha-(1)/sqrt(2)cosalpha))`
`=(sqrt(2)-sqrt(2)cos(alpha-(pi)/(4)))/(sqrt(2)sin(alpha-(pi)/(4)))`
`=(sqrt(2)(1-cos theta))/(sqrt(2)sin theta)`.
Where `theta=a-(pi)/(4)=(2sin^(2)(theta//2))/(2sin(theta//2)cos(theta//2))`
`=tan((theta)/(2))=tan((alpha)/(2)-(pi)/(8))`.
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