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Solve 2 cos^(2) theta +3 sin theta=0....

Solve `2 cos^(2) theta +3 sin theta=0`.

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We have `2 cos^(2)theta+3 sin theta=0`
or `2(1- sin^(2) theta)+3 sin theta=0`
or `2 sin^(2) theta-3 sin theta-2 =0`
or `(sin theta-2) (2 sin theta+1)=0`
or `2 sin theta+1=0" "[ :' sin theta ne 2]`
or `sin theta=-1/2=sin ((-pi)/6)`
`rArr theta = n pi+(-1)^(n) ((-pi)/6), n in Z`
`=n pi+(-1)^(n+1) pi/6, n in Z`
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