Find the number of integral value of `n`
so that `sinx(sinx+cosx)=n`
has at least one solution.
Text Solution
Verified by Experts
`sin x(sin x+cos x)=n` or `sin^(2) x+ sin x cos x =n` or `(1- cos 2x)/2+(sin 2 x)/2 =n` or `sin 2x-cos 2x=2n -1` `rArr -sqrt(2) le 2n -1 le sqrt(2)` or `(1-sqrt(2))/2 le n le (1+sqrt(2))/2` or `n=0, 1`
Topper's Solved these Questions
TRIGONOMETRIC EQUATIONS
CENGAGE|Exercise Exercise 4.1|12 Videos
TRIGONOMETRIC EQUATIONS
CENGAGE|Exercise Exercise 4.2|6 Videos
TRIGNOMETRIC RATIOS IDENTITIES AND TRIGNOMETRIC EQUATIONS
CENGAGE|Exercise Question Bank|34 Videos
TRIGONOMETRIC FUNCTIONS
CENGAGE|Exercise SINGLE CORRECT ANSWER TYPE|38 Videos
Similar Questions
Explore conceptually related problems
Find the number of integral value of n so that sin x(sin x+cos x)=n has at least one solution.
Total number of integral values of 'n' so that sinx(sinx+cosx) = n has at least one solution , is :
The number of integral values of 'k' for which the equation 3sinx + 4 cosx = k + 1 has a solution, k in R is
Find the number of integral values of k for which the equation 12cosx - 5 sinx = 2k+1 has a solution.
Find intdx/(sinx+cosx)
The equation sinx cosx=2 has:
The number of solutions of the equation 4sinx – 3cosx = 7 are
Evaluate: int(sinx+cosx)/(sinx-cosx)dx
CENGAGE-TRIGONOMETRIC EQUATIONS-Archives (Matrix Match Type)