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Given that log2 3 = a, log3 5=b,log7 2=...

Given that `log_2 3 = a, log_3 5=b,log_7 2=c`,then the value of `log_(140) 63` is equal to

A

`(2+ac)/(2c+1+abc)`

B

`(1+2ac)/(c+2+abc)`

C

`(1+2ac)/(2c+1+abc)`

D

`(2+ac)/(c+2+abc)`

Text Solution

Verified by Experts

The correct Answer is:
C
`log_(140)63=(log_(7)7+2log_(7)3)/(2log_(7)2+log_(7)7+log_(7)5)`
`=(1+2ac)/(2c+1+abc)`
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