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Which of the following is greatest ?...

Which of the following is greatest ?

A

tan 1

B

`tan^(2)1`

C

cot 1

D

`cot^(2) 1`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the following is the greatest among \( \tan 1 \), \( \tan^2 1 \), \( \cot 1 \), and \( \cot^2 1 \), we can follow these steps: ### Step 1: Understand the values of \( \tan 1 \) and \( \cot 1 \) First, we need to recognize that \( 1 \) is in radians. We know that: - \( \tan 1 \) is the tangent of \( 1 \) radian. - \( \cot 1 = \frac{1}{\tan 1} \). Since \( \tan 1 \) is greater than \( 0 \) (as \( 1 \) radian is in the first quadrant where tangent is positive), we can conclude that \( \cot 1 \) will be less than \( 1 \). ### Step 2: Compare \( \tan 1 \) and \( \cot 1 \) Since \( \tan 1 > 0 \) and \( \cot 1 < 1 \), we can establish that: \[ \tan 1 > \cot 1 \] ### Step 3: Analyze \( \tan^2 1 \) Next, we consider \( \tan^2 1 \): - Since \( \tan 1 > 1 \) (because \( \tan(\frac{\pi}{4}) = 1 \) and \( 1 \) radian is greater than \( \frac{\pi}{4} \)), squaring \( \tan 1 \) will yield a value greater than \( \tan 1 \): \[ \tan^2 1 > \tan 1 \] ### Step 4: Compare \( \cot^2 1 \) Now, we analyze \( \cot^2 1 \): - Since \( \cot 1 < 1 \), squaring it will yield a value less than \( \cot 1 \): \[ \cot^2 1 < \cot 1 < 1 \] ### Step 5: Establish the order of the values From the comparisons made: 1. \( \tan^2 1 > \tan 1 \) 2. \( \tan 1 > \cot 1 \) 3. \( \cot 1 > \cot^2 1 \) Thus, we can summarize the order as: \[ \tan^2 1 > \tan 1 > \cot 1 > \cot^2 1 \] ### Conclusion The greatest value among \( \tan 1 \), \( \tan^2 1 \), \( \cot 1 \), and \( \cot^2 1 \) is: \[ \boxed{\tan^2 1} \]

To determine which of the following is the greatest among \( \tan 1 \), \( \tan^2 1 \), \( \cot 1 \), and \( \cot^2 1 \), we can follow these steps: ### Step 1: Understand the values of \( \tan 1 \) and \( \cot 1 \) First, we need to recognize that \( 1 \) is in radians. We know that: - \( \tan 1 \) is the tangent of \( 1 \) radian. - \( \cot 1 = \frac{1}{\tan 1} \). ...
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