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If the bisector of angle A of the triang...

If the bisector of angle `A` of the triangle `ABC` makes an angle `theta` with `BC`, then `sintheta=`

A

`|sin((B-C)/(2))|`

B

`|sin((B)/(2)-C)|`

C

`cos((B-C)/(2))`

D

`cos((B)/(2)-C)`

Text Solution

Verified by Experts

The correct Answer is:
C

`theta =pi -(C+(A)/(2))`
`rArr sin theta = sin (C+(A)/(2))`
`= sin (B+(pi)/(2)-(B+C)/(2))`
`= cos ((B-C)/(2))`
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