The vector `veca+vecb` bisects the angle between the vectors `hata and hatb` if (A) `|veca|+|vecb|=0` (B) angle between `veca and vecb` is zero (C) `|veca|=|vecb|=0` (D) none of these

Explanation

We know that vector `veca+vecb` is along the diagonal of the parallelogram whose adjacent sides are vectors `veca and vecb`. Now if `veca+vecb` bisects the angle between vectors `veca and vecb`, then the parallelogram must be a rhombus , hence, `|veca|=|vecb|`.