If `veca = (-hati + hatj - hatk)` and `vecb = (2hati- 2hatj + 2hatk)` then find the unit vector in the direction of `(veca + vecb)`.

Explanation

The given vectors are `veca=2hati-hatj+2hatk and vecb=-hati+hatj-hatk`. Therefore,
`" "veca+vecb=(2-1)hati+(-1+1)hatj+(2-1)hatk=hati+hatk`
`therefore" "|veca+vecb|=sqrt(1^(2)+1^(2))=sqrt(2)`
Hence, the unit vector in the direction of `(veca+vecb)` is
`" "((veca+vecb))/(|veca+vecb|)=(hati+hatk)/(sqrt(2))=(1)/(sqrt(2))hati+(1)/(sqrt(2))hatk`