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Find the value of i^n+i^(n+1)+i^(n+2)+i^...

Find the value of `i^n+i^(n+1)+i^(n+2)+i^(n+3)` for all `n in Ndot`

A

`0`

B

`i`

C

`-i`

D

`2i ^(n)`

Text Solution

Verified by Experts

The correct Answer is:
A
`i^(n) + i^(n+1) + i^(n+2) + i^(n+3) = i^(n)[1+ i^(2)+ i^(3)]`
`=i ^(n) [ 1+ i- 1-i]`
` = i^(n) (0) = 0`
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