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For x^2-(a+3)|x|=4=0 to have real soluti...

For `x^2-(a+3)|x|=4=0` to have real solutions, the range of `a` is `(-oo,-7]uu[1,oo)` `(-3,oo)` `(-oo,-7]` `[1,oo)`

A

`(-oo,-7]cup [1,oo)`

B

`(-3,oo)`

C

`(-oo,-7]`

D

`[1,oo)`

Text Solution

Verified by Experts

The correct Answer is:
D
`a = (x^(2) + 4)/(|x|) - 3`
`= |x| + (4)/(|x|) - 3`
`ge 2 sqrt(|x| xx (4)/(|x|)) - 3`
`implies a ge 1`
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