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Discuss the extremum of f(x)={|x^2-2|,-...

Discuss the extremum of `f(x)={|x^2-2|,-1lt=x

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Verified by Experts

The correct Answer is:
Point of global maxima :x=0
Point of local minima:`x= sqrt)(2)`
Clearly from the graph given in figure `x=sqrt(2)` is point of minima
`x=sqrt(3)` is not of extremum
`x=2sqrt(3)` is also not a point of extremum
x=0 is point of maxima.
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