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Find the minimum value of |x|+|x+1/2|+|x...

Find the minimum value of `|x|+|x+1/2|+|x-3|+|x-5/2|dot`

Text Solution

Verified by Experts

The correct Answer is:
Points of minima : `[0,5//2]`
Minimum value:6
`f(x) =|x|+|x+(1)/(2)|+|x-3|+|x-(5)/(2)|`

From the graph , minimum value is 6
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