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Let f(x) =ax^(2) + bx + c and f(-1) lt 1...

Let `f(x) =ax^(2) + bx + c and f(-1) lt 1, f(1) gt -1, f(3) lt -4 and a ne 0`, then

A

`g(f(x+1))gtf(f(x-1))`

B

`f(g(x-1))gtf(f(x+1))`

C

`g(f(x+1))ltg(f(x-1))`

D

`g(f(x+1))ltg(g(x-1))`

Text Solution

Verified by Experts

The correct Answer is:
2,3

Since g(x) is increasing and f(x) is decreasing
`g(x+1)gtg(x-1)and f(x+1)ltf(x-1)`
or `f{g(x+1)}ltf{(g(x-1)}`
and `g{f(x+1)}ltg{f(x-1)}`
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