consider P(x) to be a polynomial of degree 5 having extremum at x=-1,1 and `lim_(xrarr0) p(x)/(x^(3))-2=4` Then the value of P(x)_____.

Answer

2.4

Explanation

Give `underset(xrarr0)lim p(x)/(x^(3))-2=4`
`therefore underset(xrarr0)lim(p(x))/(x^(3))=6`
consider P(x) =`ax^(5)+bx^(4)+6x^(3)`
Now `P(-1)=0 rarr5a-4b=-018`
and `P(1)=0 rarr 5a+4b=-18`
Hence P(x) =`(-18)/(5)x^(5)+6x^(3)`
or P(1)`=12/3`