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On the basis of the following E^(@) valu...

On the basis of the following `E^(@)` values, the stongest oxidizing agent is `[Fe(CN)_(6)]^(4-) rarr [Fe(CN)_(6)]^(3-)+e^(-), E^(@) = -0.35 V`
`Fe^(2+) rarr Fe^(3+)+e^(-), E^(@) = -0.77 V`

A

`Fe^(3+)`

B

`[Fe(CN)_(6)]^(3-)`

C

`[Fe(CN)_(6)]^(4-)`

D

`Fe^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:([Fe(CN)_(6)]^(3-)rarr[Fe(CN)_(6)]^(4-)",",E^(@)=+0.35V),(" "Fe^(3+)rarrFe^(2+)",",E^(@)=+0.77V):}`
Higher the positive reduction potential, stronger is the oxidizing agent. Oxidizing agent oxidizes other compounds and gets itself reduced easily.
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On the basis of the folwing E^@ values, the strongest oxidizing agent is [Fe(CN)_6 ]_4^(-) rarr [Fe(CN)_5]^(3-) +3^- , E^@ =- 0.35 V Fe^(2+) rarr Fe^(3+) + e^(- : E^@ =- 0. 77 V .

(i) On the basis of the standard electrode potential values stated for acid solutions, predict whether Ti^(4+) species may be used to oxidise Fe(II) to Fe(III) {:(Ti^(4+) + e^(-) to Ti^(3+), E^(@) = +0.01V), (Fe^(3+) + e^(-) to Fe^(2+), E^(@)= +0.77V):} (ii) Based on the data arrange Fe^(3+), Mn^(2+) " and " Cr^(2+) in the increasing order of stability of +2 oxidation state. (Give a brief reason) E_(Cr^(3+)//Cr^(2+))^(@) = -0.4V E_(Mn^(3+)//Mn^(2+))^(@) = +1.5V E_(Fe^(3+)//Fe^(2+))^(@) = +0.8V

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