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The correct of decreasing second ionisat...

The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

A

`Mn gt Cr gt Ti gt V`

B

`Ti gt V gt Cr gt Mn`

C

`Cr gt Mn gt V gt Ti`

D

`V gt Mn gt Cr gt Ti`

Text Solution

Verified by Experts

The correct Answer is:
C
As ionization enthalpy (both first and second) increases from left to right across the period. Only chromium is exceptional due to the stable configuration `(3d^(5))` so the correct order is :
`Crgt Mn gt V gt Ti`
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