Home
Class 12
CHEMISTRY
Bond dissociation enthalpy of H(2) , Cl(...

Bond dissociation enthalpy of `H_(2)` , `Cl_(2)` and `HCl` are `434, 242` and `431KJmol^(-1)` respectively. Enthalpy of formation of `HCl` is

A

`-93" kJ mol"^(-1)`

B

`245" kJ mol"^(-1)`

C

`93" kJ mol"^(-1)`

D

`-245" kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)+Cl_(2)rarr 2HCl` ltBrgt `DeltaH_("reaction")=Sigma(BE)_("reactant")-Sigma(BE)_("product")`
`=[(BE)_(H-H)+(BE)_(Cl-Cl)]-[2(BE)_(H-Cl)]`
`=434+242-(431)xx2`
`=-186kJ`
As `DeltaH_("reaction")=-186kJ`
So enthalpy of formation of HCl
`=(-186kJ)/(2)`
`=-93" kJ mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise QUESTION|92 Videos

  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise MCQ|94 Videos

  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise MCQ|94 Videos

  • METALLURGICAL OPERATIONS

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise MCQ|21 Videos

  • NEET 2018

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise QUESTION|45 Videos

Similar Questions

Explore conceptually related problems

Bond dissociation enthalpy of H_(2),Cl_(2) and HCl are 434,242 and 431kJ mol^(-1) respectively. Enthalpy of formation of HCl is :

The bond dissociation energy of gaseous H_(2), Cl_(2) and HCl are 104, 58 and 103 kcal mol^(-1) respectively. The enthalpy of formation for HCl gas will be

The bond dissociation energy of gaseous H_(2),Cl_(2) and HCl are 104,58,103 kcal mol^(-1) respectively. The enthalpy of formation for HCl gas will be :

The bond dissociation energy of gaseous H_(2),Cl_(2) and HCl are 104,58 and 103 kcal mol^(-1) respecitvely. Calculate the enthalpy of formation for HCl gas.

Calculate the bond enthalpy of H-CI given that the bond enthalpies of H_(2) and CI_(2) are 435.4 and 242.8 kJ "mol"^(-1) respectively and enthalpy of formation of HCI(g) is -92.2 kJ mol

The bond dissociation energies for Cl_(2) , I_(2) and IC l are 242.3 , 151.0 and 211.3 kJ//"mole" respectively. The enthalpy of sublimation of iodine is 62.8 kJ //"mole" . What is the standard enthalpy of formation of ICI(g) nearly equal to

NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)-NEET-CHEMISTRY
  1. Acetophenone when reacted with a base, C(2)H(5)ONa, yields a stable...

    Text Solution

    |

  2. Volume occupied by one molecule of water (density = 1 g cm^(-3))

    Text Solution

    |

  3. Bond dissociation enthalpy of H(2) , Cl(2) and HCl are 434, 242 and 43...

    Text Solution

    |

  4. Which of the following complexes exhibits the highest paramagnetic beh...

    Text Solution

    |

  5. Which one of the following statements is not true ?

    Text Solution

    |

  6. In a reactione a coloured product C was obtained The structure of C wo...

    Text Solution

    |

  7. For the gas phase reaction PCl(5)rarrPCl(3)(g)+Cl(2)(g) which of t...

    Text Solution

    |

  8. The measurement of the electron position is associated with an uncerta...

    Text Solution

    |

  9. Angular shape of ozone molecule consists of

    Text Solution

    |

  10. Percentage of free space in cubic in a body- centred cubic unit cell ...

    Text Solution

    |

  11. the value of equilibrium constant for the reaction HI(g) hArr 1//2 ...

    Text Solution

    |

  12. The values of K(p(1)) and K(p(2)) for the reactions X hArr Y+Z ….(i...

    Text Solution

    |

  13. Which of the following is an amine hormone ?

    Text Solution

    |

  14. Kohlrausch's law states that at:

    Text Solution

    |

  15. Green chemistry means such reactions which

    Text Solution

    |

  16. Which of the following statements is not correct ?

    Text Solution

    |

  17. In a S(N^(2)) substitution reaction of the type R-Br+Cl^(-)overset("...

    Text Solution

    |

  18. The correct order for bond angles is :

    Text Solution

    |

  19. With Which one of the following elements silicon should be doped so as...

    Text Solution

    |

  20. H(3)C-underset(CH(3))underset(|)(CH)-CH=CH(2)+HBr to A. A is predomi...

    Text Solution

    |