the value of equilibrium constant for the reaction
`HI(g) hArr 1//2 H_(2) (g) +1//2 I_(2) (g) " is " 8.0`
The equilibrium constant for the reaction
`H_(2) (g) +I_(2) (g) hArr 2HI(g)` will be

Options

A. 16
B. 43473
C. 43481
D. 23377

Answer

D

Explanation

`HI(g)hArr1//2H_(2)(g)+1//2I_(2)(g)`
`K=([H_(2)]^(1//2)[I_(2)]^(1//2))/([HI]_(4))=8`
`H_(2)(g)+I_(2)(q)hArr 2HI(g)`
`K'=([HI]^(2))/([H_(2)][I_(2)])=(1//8)^(2)`
`K'=1//64`